In a triangle $ABC$,if $\cos A + 2 \cos B + \cos C = 2$ and the lengths of the sides opposite to the angles $A$ and $C$ are $3$ and $7$ respectively,then $\cos A - \cos C$ is equal to

  • A
    $\frac{3}{7}$
  • B
    $\frac{9}{7}$
  • C
    $\frac{10}{7}$
  • D
    $\frac{5}{7}$

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