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(B) The dimensional formula for force is $[M L T^{-2}]$.Given,$N_1 = 10$,$M_1 = 1 \,kg$,$L_1 = 1 \,m$,$T_1 = 1 \,s$.In the new system,$M_2 = A \,kg$,$

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$10 A^{-1} B^{-1} C^2$

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(B) The dimensional formula for force is $[M L T^{-2}]$.Given,$N_1 = 10$,$M_1 = 1 \,kg$,$L_1 = 1 \,m$,$T_1 = 1 \,s$.In the new system,$M_2 = A \,kg$,$L_2 = B \,m$,$T_2 = C \,s$.Using the conversion formula $N_2 = N_1 \left( \frac{M_1}{M_2} \right)^1 \left( \frac{L_1}{L_2} \right)^1 \left( \frac{T_1}{T_2} \right)^{-2}$.Substituting the values:$N_2 = 10 \left( \frac{1}{A} \right)^1 \left( \frac{1}{B} \right)^1 \left( \frac{1}{C} \right)^{-2}$.$N_2 = 10 \cdot A^{-1} \cdot B^{-1} \cdot C^2$.Thus,the value of $10 \,N$ in the new system is $10 A^{-1} B^{-1} C^2$.

In a system,the unit of mass is $A \,kg$,length is $B \,m$,and time is $C \,s$. Then,the value of $10 \,N$ in this system is:

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