In a screw gauge,the zero of the circular scale lies $3$ divisions above the horizontal pitch line when their metallic studs are brought in contact. Using this instrument,the thickness of a sheet is measured. If the pitch scale reading is $1 \ mm$ and the circular scale reading is $51$,then the correct thickness of the sheet is . . . . . . $mm$. [Assume least count is $0.01 \ mm$]
- A$1.50$
- B$1.48$
- C$1.54$
- D$1.51$
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