In a reactor, 2, kg of { }_{92} U ^{235} fuel | vedclass

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Question

Number of uranium atoms in $2 kg$

$=\frac{2 	imes 6.023 	imes 10^{26}}{235}$

energy from one atom is $200 	imes 10^{6}$ e.v. hence total ener

Vedclass · Accepted Answer

$60$

Vedclass · Answer

Number of uranium atoms in $2 kg$

$=\frac{2 	imes 6.023 	imes 10^{26}}{235}$

energy from one atom is $200 	imes 10^{6}$ e.v. hence total energy from $2 kg$ uranium

$=\frac{2 	imes 6.023 	imes 10^{26}}{235} 	imes 200 	imes 10^{6} 	imes 1.6 	imes 10^{-19} J$

$2 kg$ uranium is used in $30$ days hence this energy is recieved in 30 days hence energy recived per second or power is

Power $=\frac{2 	imes 6.023 	imes 10^{26} 	imes 200 	imes 10^{6} 	imes 1.6 	imes 10^{-19}}{235 	imes 30 	imes 24 	imes 3600}$

Power $=63.2 	imes 10^{6}$ watt or $63.2$ Mega Watt

In a reactor, $2\, kg$ of ${ }_{92} U ^{235}$ fuel is fully used up in $30$ days. The energy released per fission is $200\, MeV.$ Given that the Avogadro number, $N =6.023 \times 10^{26}$ per kilo mole and $1\, eV =1.6 \times 10^{-19}\, J .$ The power output of the eactor is close to$.....MW$

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