The disintegration energy Q for the nuclear f | vedclass

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Question

(A) The nuclear fission reaction is: ${ }^{235} U ightarrow{ }^{140} Ce+{ }^{94} Zr+n$.The disintegration energy $Q$ is given by $Q = (m_{	ext{reac

Vedclass · Accepted Answer

$208$

Vedclass · Answer

(A) The nuclear fission reaction is: ${ }^{235} U ightarrow{ }^{140} Ce+{ }^{94} Zr+n$.The disintegration energy $Q$ is given by $Q = (m_{	ext{reactants}} - m_{	ext{products}}) c^2$.Mass of reactants $(m_{	ext{reactants}})$ = $m({ }^{235} U) = 235.0439 	ext{ u}$.Mass of products $(m_{	ext{products}})$ = $m({ }^{140} Ce) + m({ }^{94} Zr) + m(n) = 139.9054 	ext{ u} + 93.9063 	ext{ u} + 1.0086 	ext{ u} = 234.8203 	ext{ u}$.Mass defect $\Delta m = m_{	ext{reactants}} - m_{	ext{products}} = 235.0439 	ext{ u} - 234.8203 	ext{ u} = 0.2236 	ext{ u}$.Disintegration energy $Q = \Delta m 	imes 931 	ext{ MeV/u} = 0.2236 	imes 931 	ext{ MeV} = 208.1716 	ext{ MeV}$.Rounding to the nearest integer,$Q \approx 208 	ext{ MeV}$.

Similar Questions

$A$ nucleus with mass number $240$ breaks into two fragments each of mass number $120$. The binding energy per nucleon of the unfragmented nucleus is $7.6 \, MeV$,while that of the fragments is $8.5 \, MeV$. The total gain in the binding energy in the process is (in $MeV$):

Fusion reaction takes place at high temperature because

For the following two nuclear reactions,the atomic number and mass number of nuclei $X$ and $Y$ are respectively:
$(I) \, _{92}^{235}U + _{0}^{1}n \rightarrow X + _{35}^{85}Br + 3 _{0}^{1}n$
$(II) \, _{3}^{6}Li + _{1}^{2}H \rightarrow Y + _{2}^{4}He$

Which one of the following statements about uranium is correct?

Assertion : Energy is released in nuclear fission.
Reason : Total binding energy of the fission fragments is larger than the total binding energy of the parent nucleus.

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