In a parabola spectrograph, the velocities of | vedclass

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Question

(a) $\because \;x \propto \frac{1}{{{v^2}}}.$  The ion whose deflection is less, its velocity will be more. From the curve ${x_1} < {x_2} <

Vedclass · Accepted Answer

${v_1} > {v_2} > {v_3} > {v_4}$

Vedclass · Answer

(a) $\because \;x \propto \frac{1}{{{v^2}}}.$ The ion whose deflection is less, its velocity will be more. From the curve ${x_1} < {x_2} < {x_3} < {x_4}$, $ herefore {v_1} > {v_2} > {v_3} > {v_4}$.

In a parabola spectrograph, the velocities of four positive ions $P,Q,R$ and $S$ are $v_1$, $v_2$, $v_3$ and $v_4$ respectively

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