(C) In a velocity selector,the electric force $F_e = qE$ and the magnetic force $F_m = qvB$ act in opposite directions.For the ions to pass undeflecte

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(C) In a velocity selector,the electric force $F_e = qE$ and the magnetic force $F_m = qvB$ act in opposite directions.For the ions to pass undeflected,the forces must be balanced: $qE = qvB$,which simplifies to $v = \frac{E}{B}$.The electric field $E$ between the plates is given by $E = \frac{V}{d}$.Given $V = 1000 \ V$ and $d = 1 \ cm = 0.01 \ m = 10^{-2} \ m$.$E = \frac{1000}{10^{-2}} = 10^5 \ V/m$.Given $B = 1 \ T$.Substituting these values into the velocity formula: $v = \frac{10^5}{1} = 10^5 \ m/s$.

Class 12 Physics Moving Charges and Magnetism Motion of Charged Particle In Magnetic Field

Medium

In a Bainbridge mass spectrograph,a potential difference of $1000 \ V$ is applied between two plates separated by a distance of $1 \ cm$. If the magnetic field is $B = 1 \ T$,what is the velocity of the undeflected positive ions in $m/s$ from the velocity selector?

A
$10^7 \ m/s$
B
$10^4 \ m/s$
C
$10^5 \ m/s$
D
$10^2 \ m/s$

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Moving Charges and Magnetism

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Motion of Charged Particle In Magnetic Field

$A$ particle of mass $m = 1.67 \times 10^{-27} \, kg$ and charge $q = 1.6 \times 10^{-19} \, C$ enters a region of uniform magnetic field of strength $B = 1 \, T$ as shown in the figure. The angle of incidence is $45^{\circ}$. The radius of the circular portion of the path is:

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In a Bainbridge mass spectrograph,a potential difference of $1000 \ V$ is applied between two plates separated by a distance of $1 \ cm$. If the magnetic field is $B = 1 \ T$,what is the velocity of the undeflected positive ions in $m/s$ from the velocity selector?

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$A$ particle of mass $m = 1.67 \times 10^{-27} \, kg$ and charge $q = 1.6 \times 10^{-19} \, C$ enters a region of uniform magnetic field of strength $B = 1 \, T$ as shown in the figure. The angle of incidence is $45^{\circ}$. The radius of the circular portion of the path is:

$A$ singly ionized magnesium atom $(A=24)$ ion is accelerated to kinetic energy $5\,keV$ and is projected perpendicularly into a magnetic field $B$ of magnitude $0.5\,T$. The radius of the path formed will be . . . . . . $cm$.

Two particles $X$ and $Y$ having equal charges are being accelerated through the same potential difference. Thereafter,they enter normally into a region of uniform magnetic field and describe circular paths of radii $R_1$ and $R_2$ respectively. The mass ratio of $X$ and $Y$ is:

Two particles $X$ and $Y$ having equal charges,are accelerated through the same potential difference. They enter a region of a uniform magnetic field and describe a circular path of radii $r_1$ and $r_2$ respectively. The ratio of the mass of $X$ to that of $Y$ is

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