In a maths test taken by $40$ students,the average score of $30$ boys is $16$ and the average score of $10$ girls is $12$. Which of the following gives the average score of the whole class?

  • A
    $\frac{16+12}{2}$
  • B
    $\frac{(30 \times 16)+(10 \times 12)}{30+10}$
  • C
    $\frac{(30 \times 12)+(10 \times 16)}{12+16}$
  • D
    $\frac{(30 \times 10)+(16 \times 12)}{30+10}$

Explore More

Similar Questions

Consider the following distribution:
Marks obtainedNumber of students
More than or equal to $0$$63$
More than or equal to $10$$58$
More than or equal to $20$$55$
More than or equal to $30$$51$
More than or equal to $40$$48$
More than or equal to $50$$42$

The frequency of the class $30-40$ is:

In the formula $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{\Sigma f_{i}}$ for the mean,$d_{i} = \dots$

The median class in the following frequency distribution is ..........
Class $20-25$ $25-30$ $30-35$ $35-40$ $40-45$ $45-50$ $50-55$
Frequency $2$ $5$ $8$ $10$ $7$ $10$ $3$

The following table shows the cumulative frequency distribution of marks of $800$ students in an examination:
Marks Number of students
Below $10$ $10$
Below $20$ $50$
Below $30$ $130$
Below $40$ $270$
Below $50$ $440$
Below $60$ $570$
Below $70$ $670$
Below $80$ $740$
Below $90$ $780$
Below $100$ $800$

Construct a frequency distribution table for the data above.

If $x_{i}$ are the midpoints of the class intervals of grouped data,$f_{i}$ are the corresponding frequencies,and $\bar{x}$ is the mean,then $\sum (f_{i} x_{i} - f_{i} \bar{x})$ is equal to

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo