The following table shows the cumulative frequency distribution of marks of $800$ students in an examination:
Marks Number of students Below $10$ $10$ Below $20$ $50$ Below $30$ $130$ Below $40$ $270$ Below $50$ $440$ Below $60$ $570$ Below $70$ $670$ Below $80$ $740$ Below $90$ $780$ Below $100$ $800$
Construct a frequency distribution table for the data above.
| Marks | Number of students |
| Below $10$ | $10$ |
| Below $20$ | $50$ |
| Below $30$ | $130$ |
| Below $40$ | $270$ |
| Below $50$ | $440$ |
| Below $60$ | $570$ |
| Below $70$ | $670$ |
| Below $80$ | $740$ |
| Below $90$ | $780$ |
| Below $100$ | $800$ |
Construct a frequency distribution table for the data above.
(N/A) To construct the frequency distribution table,we subtract the cumulative frequency of the previous class from the current class to find the frequency of each class interval.
| Class interval | Number of students (Frequency) |
| $0-10$ | $10$ |
| $10-20$ | $50 - 10 = 40$ |
| $20-30$ | $130 - 50 = 80$ |
| $30-40$ | $270 - 130 = 140$ |
| $40-50$ | $440 - 270 = 170$ |
| $50-60$ | $570 - 440 = 130$ |
| $60-70$ | $670 - 570 = 100$ |
| $70-80$ | $740 - 670 = 70$ |
| $80-90$ | $780 - 740 = 40$ |
| $90-100$ | $800 - 780 = 20$ |
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Similar Questions
Find the mean of the following data by all the three methods:
Class $50-70$ $70-90$ $90-110$ $110-130$ $130-150$ $150-170$ Frequency $10$ $18$ $7$ $6$ $5$ $4$
| Class | $50-70$ | $70-90$ | $90-110$ | $110-130$ | $130-150$ | $150-170$ |
| Frequency | $10$ | $18$ | $7$ | $6$ | $5$ | $4$ |
Medium
View Solution.......... is not a measure of central tendency.
Easy
View SolutionConsider the following frequency distribution of the heights of $60$ students of a class:
Height (in $cm$) Number of students $150-155$ $15$ $155-160$ $13$ $160-165$ $10$ $165-170$ $8$ $170-175$ $9$ $175-180$ $5$
The sum of the lower limit of the modal class and upper limit of the median class is:
| Height (in $cm$) | Number of students |
| $150-155$ | $15$ |
| $155-160$ | $13$ |
| $160-165$ | $10$ |
| $165-170$ | $8$ |
| $170-175$ | $9$ |
| $175-180$ | $5$ |
The sum of the lower limit of the modal class and upper limit of the median class is:
Easy
View SolutionIf $M = 72$ and $\bar{x} = 70$,then $Z = \ldots \ldots \ldots \ldots$
Medium
View SolutionFind the mean,median,and mode of the following frequency distribution:
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ Frequency $4$ $6$ $8$ $12$ $10$ $5$ $5$
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ |
|---|---|---|---|---|---|---|---|
| Frequency | $4$ | $6$ | $8$ | $12$ | $10$ | $5$ | $5$ |
Medium
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