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(C) Sickle cell anaemia is an autosomal recessive disorder.Let the normal allele be $Hb^A$ and the sickle cell allele be $Hb^S$.Both parents are heter

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(C) Sickle cell anaemia is an autosomal recessive disorder.Let the normal allele be $Hb^A$ and the sickle cell allele be $Hb^S$.Both parents are heterozygous, meaning their genotypes are $Hb^A Hb^S$.The cross is: $Hb^A Hb^S 	imes Hb^A Hb^S$.The Punnett square results are:$1$ $Hb^A Hb^A$ (Normal)$2$ $Hb^A Hb^S$ (Carrier/Heterozygous)$1$ $Hb^S Hb^S$ (Diseased)Thus, $1$ out of $4$ offspring will be diseased.Percentage = $(1/4) 	imes 100 = 25\%$.

In a cross between a male and female, both heterozygous for sickle cell anaemia gene, what percentage of the progeny will be diseased? (In $ \%$ )

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