Colour blindness is a disease usually affecting man but the factor for it is transmitted to the children always by woman. This is because particular factor is located on
$X$ chromosome
$Y$ chromosome
Both $X$ and $Y$ chromosomes
Autosome
A man with normal vision whose father was colourblind marries with women whose father was also colourblind. Suppose their first child is daughter then what are the chances of this child to be colourblind?
A normal woman whose father was colourblind marries a normal man. What kinds of children would be expected and in what proportion
:Match the columns :
Column $I$ |
Column $II$ |
$(1)$ Albinism | $(p)$ recessive gene represented by HbsHbs. |
$(2)$ Phenyl Ketonuria |
$(q)$ recessive gene represented by cc. |
$(3)$ Sickle cell anaemia |
$(r)$ recessive gene represented by aa. |
$4)$ Alkaptonuria | $(s)$ recessive gene represented by pp |
Following characters are indicate
$(i)$ presence of sickle - shaped $RBC$
$(ii)$ Blood not clot, non stop bleeding
$(iii)$ The heterozygous female transmit the disease to sons.
$(iv)$ Both heterozygous parents transmit the disease to offspring
Among symbol $A, B$ and $C, C$ indicates