In a city,it is found that 10 accidents took | vedclass

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Question

(B) Let $X$ be the random variable representing the number of accidents in a day. $X \sim 	ext{Poisson}(\lambda)$.Given that $10$ accidents occurred

Vedclass · Accepted Answer

$1-(1.22) e^{-0.2}$

Vedclass · Answer

(B) Let $X$ be the random variable representing the number of accidents in a day. $X \sim 	ext{Poisson}(\lambda)$.Given that $10$ accidents occurred in $50$ days,the mean rate $\lambda$ per day is $\lambda = \frac{10}{50} = 0.2$.The probability of $X$ accidents in a day is given by $P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!}$.We need to find $P(X \geq 3) = 1 - [P(X=0) + P(X=1) + P(X=2)]$.$P(X \geq 3) = 1 - \left[ \frac{e^{-0.2} (0.2)^0}{0!} + \frac{e^{-0.2} (0.2)^1}{1!} + \frac{e^{-0.2} (0.2)^2}{2!} ight]$.$P(X \geq 3) = 1 - e^{-0.2} \left[ 1 + 0.2 + \frac{0.04}{2} ight]$.$P(X \geq 3) = 1 - e^{-0.2} [1 + 0.2 + 0.02] = 1 - 1.22 e^{-0.2}$.

$X = x$	$0$	$1$	$2$	$3$	$4$	$5$	$6$	$7$
$P(X = x)$	$0$	$k$	$2k$	$2k$	$3k$	$k^2$	$2k^2$	$7k^2 + k$

$X = x$	$0$	$1$	$2$	$3$	$4$	$5$	$6$	$7$	$8$
$P(x)$	$k$	$2k$	$3k$	$4k$	$4k$	$3k$	$2k$	$k$	$k$

$X$	$0$	$1$	$2$
$P(X)$	$\frac{25}{36}$	$k$	$\frac{1}{36}$

In a city,it is found that $10$ accidents took place in a span of $50$ days. Assuming that the number of accidents follows the Poisson distribution,the probability that there will be $3$ or more accidents in a day in that city is

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