In a chemical reaction $A$ is converted into $B$ . The rates of reaction, starting with initial concentrations of $A$ as $2 \times {10^{ - 3}}\,M$ and $1 \times {10^{ - 3}}\,M$ , are equal to $2.40 \times {10^{ - 4}}\,M{s^{ - 1}}$ and $0.60 \times {10^{ - 4}}\,M{s^{ - 1}}$ respectively. The order of reaction with respect to reactant $A$ will be

  • [AIEEE 2012]
  • A

    $0$

  • B

    $1.5$

  • C

    $1$

  • D

    $2$

Similar Questions

A reaction involving two different reactants

  • [AIEEE 2005]

For the reaction

$2 \mathrm{H}_{2}(\mathrm{g})+2 \mathrm{NO}(\mathrm{g}) \rightarrow \mathrm{N}_{2}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})$

the observed rate expression is, rate $=\mathrm{k}_{\mathrm{f}}[\mathrm{NO}]^{2}\left[\mathrm{H}_{2}\right] .$ The rate expression of the reverse reaction is

  • [JEE MAIN 2020]

For a general reaction $A \to B$, plot of concentration of $A$ vs time is given in figure. Answer the following question on the basis of this graph.

$(i)$ What is the order of the reaction ?

$(ii)$ What is the slope of the curve ?

$(iii)$ What are the units of rate constant ?

Consider the data given below for hypothetical reaction $A \to X$

$Time  (sec)$                     Rate $(mol\,  L^{-1} sec.^{-1})$

$0$                                      $1.60 \times 10^{-2}$

$10$                                    $1.60 \times 10^{-2}$

$20$                                    $1.60 \times 10^{-2}$

$30$                                    $1.60 \times 10^{-2}$

From the above data, the order of reaction is

In the reaction $A + B \to $ Products, if $B$ is taken in excess, then it is an example of