Consider the data given below for the hypothetical reaction $A \to X$:

$Time \ (s)$	$Rate \ (mol \ L^{-1} s^{-1})$
$0$	$1.60 \times 10^{-2}$
$10$	$1.60 \times 10^{-2}$
$20$	$1.60 \times 10^{-2}$
$30$	$1.60 \times 10^{-2}$

From the above data,the order of the reaction is:

In the following reaction $A \to B + C,$ the rate constant is $0.001 \ M \ s^{-1}.$ If we start with $1 \ M$ of $A,$ then the concentrations of $A$ and $B$ after $10 \ minutes$ are respectively:

$A$ substance (initial concentration $= a$) reacts according to zero order kinetics. The time taken for the completion of reaction is nearly

If the slope of a line of the graph between dissociated concentration of reactant $([A]_0 - [A]_t)$ and time ($t$ in $min$) for a zero order reaction is $0.02 \ mol \ L^{-1} \ min^{-1}$,then calculate the initial concentration of reactant $([A]_0)$,if after $30 \ min$ its concentration $([A]_t)$ is $0.05 \ mol \ L^{-1}$. (in $M$)

Provide the graphs for a zero-order reaction and explain the information obtained from them.

For a zero order reaction $A \rightarrow \text{product}$,a plot of $[A]$ (on $y$-axis) and time (on $x$-axis) gave a straight line with slope equal to $-3 \times 10^{-3} \ M \ min^{-1}$ and intercept equal to $2 \times 10^{-2} \ M$ (on $y$-axis). What is the rate constant (in $M \ min^{-1}$) of this reaction?