In a charged capacitor,the energy resides in:

$A$ parallel plate capacitor having plate area $A$ and separation $d$ is charged to a potential difference $V$. The charging battery is disconnected and the plates are pulled apart to four times the initial separation. The work required to increase the distance between the plates is ($\epsilon_0 =$ permittivity of free space).

Energy per unit volume for a capacitor having area $A$ and separation $d$ kept at potential difference $V$ is given by

$A$ $4\, \mu F$ capacitor is charged to $400\, V$ and then its plates are connected through a resistance. The heat produced in the resistance is ....... $J$.

If the charge on the capacitor is increased by $3 \ C$,the energy stored in it increases by $44 \%$. The original charge on the capacitor is (in $C$)

$A$ parallel plate capacitor has a potential of $20 \, kV$ and a capacitance of $2 \times 10^{-4} \, \mu F$. If the area of the plates is $0.01 \, m^2$ and the distance between the plates is $2 \, mm$,find the energy stored in the capacitor.