(B) Initial energy stored in the two capacitors is:$U_i = \frac{1}{2} C V^2 + \frac{1}{2} C V^2 = C V^2$When the capacitors are connected with opposit

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(B) Initial energy stored in the two capacitors is:$U_i = \frac{1}{2} C V^2 + \frac{1}{2} C V^2 = C V^2$When the capacitors are connected with opposite polarities,the net charge on the system becomes:$Q_{net} = (+CV) + (-CV) = 0$Since the total charge is zero,the final potential difference across the capacitors is zero,and thus the final energy stored is:$U_f = 0$The loss of energy is given by:$\Delta U = U_i - U_f = C V^2 - 0 = C V^2$

Class 12 Physics Electric Potential and Capacitance Sharing of Charge in Capacitor Circuit

Easy

Two identical capacitors are connected in parallel across a potential difference $V$. After they are fully charged,the positive plate of the first capacitor is connected to the negative plate of the second,and the negative plate of the first is connected to the positive plate of the other. The loss of energy will be

A
$\frac{1}{2} C V^2$
B
$C V^2$
C
$\frac{1}{4} C V^2$
D
$0$

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Class 12

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Electric Potential and Capacitance

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Sharing of Charge in Capacitor Circuit

$A$ parallel plate capacitor of capacitance $500 \ pF$ is charged with a $100 \ V$ supply. It is then disconnected from the supply and connected to another uncharged $500 \ pF$ capacitor. The electrostatic energy lost in this process is (in $\mu J$)

MediumAP EAMCET 2022

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When two isolated conductors $A$ and $B$ are connected by a conducting wire,positive charge will flow from:

Medium

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In the circuit shown in the figure,initially $K_1$ is closed and $K_2$ is open. What are the charges on each capacitor? Then $K_1$ was opened and $K_2$ was closed (order is important),what will be the charge on each capacitor now? [Given: $C = 1 \,\mu F$,$C_1 = 6C$,$C_2 = 3C$,$C_3 = 3C$,$E = 9 \, V$]

Medium

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$A$ capacitor $C$ is fully charged with voltage $V_{0}$. After disconnecting the voltage source,it is connected in parallel with another uncharged capacitor of capacitance $\frac{C}{2}$. The energy loss in the process after the charge is distributed between the two capacitors is $.........$ $CV_{0}^{2}$.

DifficultJEE MAIN 2020

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Two identical capacitors each of capacitance $5 \mu F$ are charged to potentials $2 kV$ and $1 kV$ respectively. Their negative ends are connected together. When the positive ends are also connected together,the loss of energy of the system is

DifficultKCET 2007

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$A$ parallel plate capacitor of capacitance $500 \ pF$ is charged with a $100 \ V$ supply. It is then disconnected from the supply and connected to another uncharged $500 \ pF$ capacitor. The electrostatic energy lost in this process is (in $\mu J$)

When two isolated conductors $A$ and $B$ are connected by a conducting wire,positive charge will flow from:

Two identical capacitors each of capacitance $5 \mu F$ are charged to potentials $2 kV$ and $1 kV$ respectively. Their negative ends are connected together. When the positive ends are also connected together,the loss of energy of the system is

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