(B) Initial energy stored in the two capacitors is:$U_i = \frac{1}{2} C V^2 + \frac{1}{2} C V^2 = C V^2$When the capacitors are connected with opposit

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(B) Initial energy stored in the two capacitors is:$U_i = \frac{1}{2} C V^2 + \frac{1}{2} C V^2 = C V^2$When the capacitors are connected with opposite polarities,the net charge on the system becomes:$Q_{net} = (+CV) + (-CV) = 0$Since the total charge is zero,the final potential difference across the capacitors is zero,and thus the final energy stored is:$U_f = 0$The loss of energy is given by:$\Delta U = U_i - U_f = C V^2 - 0 = C V^2$

Class 12 Physics Electric Potential and Capacitance Sharing of Charge in Capacitor Circuit

Easy

Two identical capacitors are connected in parallel across a potential difference $V$. After they are fully charged,the positive plate of the first capacitor is connected to the negative plate of the second,and the negative plate of the first is connected to the positive plate of the other. The loss of energy will be

A
$\frac{1}{2} C V^2$
B
$C V^2$
C
$\frac{1}{4} C V^2$
D
$0$

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Class 12 Questions

Class 12

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Chapter

Electric Potential and Capacitance

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Sharing of Charge in Capacitor Circuit

Two capacitors of capacitance $2 \ \mu F$ and $5 \ \mu F$ are charged to $2 \ V$ and $10 \ V$ respectively. Find the ratio of their charges after they are connected by a wire.

Medium

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An uncharged parallel plate capacitor having a dielectric of constant $K$ is connected to a similar air-cored parallel capacitor charged to a potential $V$. The two share the charge and the common potential is $V'$. The dielectric constant $K$ is

Medium

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Two capacitors of $10 \ pF$ and $20 \ pF$ are connected to $200 \ V$ and $100 \ V$ sources respectively. If they are connected by a wire,what is the common potential of the capacitors (in $V$)?

MediumKCET 2014

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$A$ capacitor of $10\,\mu F$ charged up to $250\,V$ is connected in parallel with another capacitor of $5\,\mu F$ charged up to $100\,V$. The common potential is.....$V$.

Medium

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$A$ parallel plate capacitor of capacitance $10 \mu F$ is charged by a $220 \text{ V}$ supply. The capacitor is then disconnected from the supply and is connected to another uncharged parallel plate capacitor of capacitance $12 \mu F$. The loss of electrostatic energy in this process is (in $\text{ mJ}$)

MediumTS EAMCET 2025

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Two capacitors of capacitance $2 \ \mu F$ and $5 \ \mu F$ are charged to $2 \ V$ and $10 \ V$ respectively. Find the ratio of their charges after they are connected by a wire.

An uncharged parallel plate capacitor having a dielectric of constant $K$ is connected to a similar air-cored parallel capacitor charged to a potential $V$. The two share the charge and the common potential is $V'$. The dielectric constant $K$ is

Two capacitors of $10 \ pF$ and $20 \ pF$ are connected to $200 \ V$ and $100 \ V$ sources respectively. If they are connected by a wire,what is the common potential of the capacitors (in $V$)?

$A$ capacitor of $10\,\mu F$ charged up to $250\,V$ is connected in parallel with another capacitor of $5\,\mu F$ charged up to $100\,V$. The common potential is.....$V$.

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