$A$ capacitor has a capacity of $2\,\mu F$ and is charged to a voltage of $50\,V$. The energy stored is:

If the distance between the plates of a capacitor with capacitance $C$ and charge $Q$ is doubled,the work done is:

The heat generated through $2 \, \Omega$ and $8 \, \Omega$ resistances separately, when a capacitor of $200 \, \mu F$ capacity charged to $200 \, V$ is discharged one by one, will be

$A$ parallel plate capacitor has a uniform electric field $E \ (V/m)$ in the space between the plates. If the distance between the plates is $d \ (m)$ and the area of each plate is $A \ (m^2)$,then the energy (joules) stored in the capacitor is:

If the charge on a capacitor is increased by $2 \ C$,the energy stored in it increases by $21 \%$. The original charge on the capacitor is (in $C$)

$A$ battery is used to charge a parallel plate capacitor until the potential difference between the plates becomes equal to the e.m.f. of the battery. The ratio of the energy stored in the capacitor to the work done by the battery will be