In a Boolean Algebra $B$,for all $x, y \in B$,$x \wedge (x \vee y)$ is equal to

If $p, q$ and $r$ are three propositions,then which of the following combination of truth values of $p, q$ and $r$ makes the logical expression $\{(p \vee q) \wedge ((\sim p) \vee r)\} \rightarrow ((\sim q) \vee r)$ false?

$(\sim (\sim p)) \wedge q$ is equal to .........

Let $p$ and $q$ be two statements. Amongst the following,the statement that is equivalent to $p \to q$ is

The Boolean expression $(p \wedge \sim q) \Rightarrow (q \vee \sim p)$ is equivalent to:

The contrapositive statement of the statement "If $x$ is a prime number,then $x$ is odd" is