In a $\Delta ABC,$ let $\angle C = \frac{\pi}{2}.$ If $r$ and $R$ are the inradius and the circumradius respectively of the triangle,then $2(r + R)$ is equal to

  • A
    $a + b$
  • B
    $b + c$
  • C
    $c + a$
  • D
    $a + b + c$

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