In $O_2^-$ , $O_2$ and $O_2^{2-}$ , the total number of antibonding electrons respectively are
$7, 6, 8$
$1, 0, 2$
$6, 6, 6$
$8, 6, 8$
Match List $I$ with List $II$ :
List $I$ (Molecule Species) |
List $I$ ( Property Shape ) |
$A$ $\mathrm{SO}_2 \mathrm{Cl}_2$ | $I$ Paramagnetic |
$B$ $NO$ | $II$ Diamagnetic |
$C$ $\mathrm{NO}_2^{-}$ | $III$ Tetrahedral |
$D$ $\mathrm{I}_3^{-}$ | $IV$ Linear |
Choose the correct answer from the options given below :
The species having bond order different from that in $\mathrm{CO}$ is
Two homo-diatomic molecules $'X'_2$ and $'Y'_2$ have same bond order then select the CORRECT statement
Which of the following pairs have identical values of bond order ?
For $F_2$ and $OF$ molecules consider the following statements
$(a)$ Bond order for both is one
$(b)$ $OF$ is paramagnetic but $F_2$ is diamagnetic
$(c)$ $F_2$ is more likely to dissociate into atoms than $OF$
$(d)$ Both have greater number of electrons in $BMO$ than that in $ABMO$
Which of the following statements are true $(T)$ or false $(F)$ respectively