Toluene $\xrightarrow[{heat}]{{NBS\,/\,CCl_4}} A$ $\xrightarrow{{CH_3ONa}} B,$
The final product $(B)$ formed in the reaction sequence is:

The correct order of reactivity of $CH_3Br$ in methanol with the following nucleophiles is:
$F^{-}, I^{-}, C_2H_5O^{-}$ and $C_6H_5O^{-}$

$A$ dihaloalkane '$X$',having formula $C_{3}H_{6}Cl_{2}$,on hydrolysis gives a compound that can reduce Tollen's reagent. The compound '$X$' is

The arrangement of the following compounds in the increasing order of their boiling points is:
$i$. bromomethane
$ii$. bromoform
$iii$. chloromethane
$iv$. dibromomethane

Which of the following compounds would undergo $S_N1$ reaction faster and why?
$(A)$ Cyclohexylmethyl chloride
$(B)$ Benzyl chloride

Among the given halides,which one will give the same product in both $S_{N^1}$ and $S_{N^2}$ reactions?
$(I) \ CH_3-CH(CH_3)-CH_2-CH(Br)-CH_3$
$(II) \ \text{2-methylcyclohexyl chloride}$
$(III) \ \text{Chlorocyclohexane}$
$(IV) \ CH_3-CH(Br)-CH_2-CH_3$