The arrangement of the following compounds in | vedclass

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(A) The boiling point of haloalkanes increases with an increase in the molecular mass and the number of halogen atoms due to stronger van der Waals fo

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$iii < i < iv < ii$

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(A) The boiling point of haloalkanes increases with an increase in the molecular mass and the number of halogen atoms due to stronger van der Waals forces of attraction.Comparing the compounds:$iii$. Chloromethane ($CH_{3}Cl$,molar mass $\approx 50.5 \ g/mol$)$i$. Bromomethane ($CH_{3}Br$,molar mass $\approx 95 \ g/mol$)$iv$. Dibromomethane ($CH_{2}Br_{2}$,molar mass $\approx 173.8 \ g/mol$)$ii$. Bromoform ($CHBr_{3}$,molar mass $\approx 252.7 \ g/mol$)Thus,the increasing order of boiling points is $iii < i < iv < ii$.

The arrangement of the following compounds in the increasing order of their boiling points is:
$i$. bromomethane
$ii$. bromoform
$iii$. chloromethane
$iv$. dibromomethane

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The arrangement of the following compounds in the increasing order of their boiling points is:$i$. bromomethane$ii$. bromoform$iii$. chloromethane$iv$. dibromomethane