The correct order of reactivity of CH_3Br in | vedclass

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(B) In a polar protic solvent like methanol,nucleophilicity is determined by the ability of the nucleophile to donate an electron pair. The order of n

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$I^{-} > C_2H_5O^{-} > C_6H_5O^{-} > F^{-}$

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(B) In a polar protic solvent like methanol,nucleophilicity is determined by the ability of the nucleophile to donate an electron pair. The order of nucleophilicity is governed by basicity and polarizability. $C_2H_5O^{-}$ is a strong base and a good nucleophile. $C_6H_5O^{-}$ (phenoxide) is less basic than $C_2H_5O^{-}$ due to resonance stabilization of the negative charge on the oxygen atom. $I^{-}$ is a very good nucleophile in polar protic solvents due to its high polarizability,despite being a weak base. $F^{-}$ is a small,highly solvated ion in methanol,making it a poor nucleophile. Thus,the correct order is $I^{-} > C_2H_5O^{-} > C_6H_5O^{-} > F^{-}$.

The correct order of reactivity of $CH_3Br$ in methanol with the following nucleophiles is:
$F^{-}, I^{-}, C_2H_5O^{-}$ and $C_6H_5O^{-}$

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The correct order of reactivity of $CH_3Br$ in methanol with the following nucleophiles is: $F^{-}, I^{-}, C_2H_5O^{-}$ and $C_6H_5O^{-}$