If three vectors along coordinate axis represent the adjacent sides of a cube of length $b$, then the unit vector along its diagonal passing through the origin will be
- A$\frac{\hat{ i }+\hat{ j }+\hat{ k }}{\sqrt{2}}$
- B$\frac{\hat{ i }+\hat{ j }+\hat{ k }}{\sqrt{36}}$
- C$\hat{ i }+\hat{ j }+\hat{ k }$
- D$\frac{\hat{ i }+\hat{ j }+\hat{ k }}{\sqrt{3}}$
Similar Questions
Two vectors of magnitude $3$ & $4$ have resultant which make angle $\alpha$ & $\beta$ respectively with them $\{given\, \alpha + \beta \neq 90^o\}$
Two vectors of magnitude $3$ & $4$ have resultant which make angle $\alpha$ & $\beta$ respectively with them $\{given\, \alpha + \beta \neq 90^o\}$
The vector projection of a vector $3\hat i + 4\hat k$ on $Y-$axis is
The vector projection of a vector $3\hat i + 4\hat k$ on $Y-$axis is
A vector in $x-y$ plane makes an angle of $30^{\circ}$ with $y$-axis The magnitude of $y$-component of vector is $2 \sqrt{3}$. The magnitude of $x$-component of the vector will be
A vector in $x-y$ plane makes an angle of $30^{\circ}$ with $y$-axis The magnitude of $y$-component of vector is $2 \sqrt{3}$. The magnitude of $x$-component of the vector will be
- [JEE MAIN 2023]
Following forces start acting on a particle at rest at the origin of the co-ordinate system simultaneously${\overrightarrow F _1} = - 4\hat i - 5\hat j + 5\hat k$, ${\overrightarrow F _2} = 5\hat i + 8\hat j + 6\hat k$, ${\overrightarrow F _3} = - 3\hat i + 4\hat j - 7\hat k$ and ${\overrightarrow F _4} = 2\hat i - 3\hat j - 2\hat k$ then the particle will move
Following forces start acting on a particle at rest at the origin of the co-ordinate system simultaneously${\overrightarrow F _1} = - 4\hat i - 5\hat j + 5\hat k$, ${\overrightarrow F _2} = 5\hat i + 8\hat j + 6\hat k$, ${\overrightarrow F _3} = - 3\hat i + 4\hat j - 7\hat k$ and ${\overrightarrow F _4} = 2\hat i - 3\hat j - 2\hat k$ then the particle will move