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(B) To find the direction of motion,we calculate the net force ${\vec F_{net}}$ acting on the particle: ${\vec F_{net}} = {\vec F_1} + {\vec F_2} + {\

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In $y-z$ plane

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(B) To find the direction of motion,we calculate the net force ${\vec F_{net}}$ acting on the particle: ${\vec F_{net}} = {\vec F_1} + {\vec F_2} + {\vec F_3} + {\vec F_4}$ ${\vec F_{net}} = (-4\hat i + 5\hat i - 3\hat i + 2\hat i) + (-5\hat j + 8\hat j + 4\hat j - 3\hat j) + (5\hat k + 6\hat k - 7\hat k - 2\hat k)$ ${\vec F_{net}} = (0)\hat i + (4)\hat j + (2)\hat k$ ${\vec F_{net}} = 4\hat j + 2\hat k$ Since the net force has components only along the $y$ and $z$ axes (the $x$-component is $0$),the particle will move in the $y-z$ plane.

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