If the vectors $\vec{AB} = p \hat{i} + q \hat{j} + r \hat{k}$,$\vec{AC} = s \hat{i} + 3 \hat{j} + 4 \hat{k}$,and $\vec{CB} = 3 \hat{i} + \hat{j} - 2 \hat{k}$ form a $\triangle ABC$,then the values of $p, q, r$ and $s$ such that the area of that $\triangle ABC$ is $5 \sqrt{6}$ are:

  • A
    $p=11, q=4, r=-2, s=8$
  • B
    $p=8, q=4, r=2, s=5$
  • C
    $p=-5, q=4, r=2, s=-8$
  • D
    $p=14, q=4, r=2, s=11$

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