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(B) In $\Delta ABC$,the vectors representing the sides are $BC = a$,$CA = b$,and $AB = c$. By the triangle law of vector addition,the sum of vectors a

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$a 	imes b = b 	imes c = c 	imes a$

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(B) In $\Delta ABC$,the vectors representing the sides are $BC = a$,$CA = b$,and $AB = c$. By the triangle law of vector addition,the sum of vectors along the perimeter of a triangle in order is zero: $a + b + c = 0$. Taking the cross product with $a$ on both sides: $a 	imes (a + b + c) = a 	imes 0 \implies a 	imes a + a 	imes b + a 	imes c = 0$. Since $a 	imes a = 0$,we get $a 	imes b = c 	imes a$ (as $a 	imes c = -c 	imes a$). Similarly,taking the cross product with $b$: $b 	imes (a + b + c) = b 	imes 0 \implies b 	imes a + b 	imes b + b 	imes c = 0$. Since $b 	imes b = 0$,we get $b 	imes a + b 	imes c = 0 \implies b 	imes c = a 	imes b$. Combining these,we have $a 	imes b = b 	imes c = c 	imes a$.

If the vectors $a, b$ and $c$ are represented by the sides $BC, CA$ and $AB$ respectively of the $\Delta ABC$,then

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