If the system of equations, $a^2 x - ay = 1 - a$ & $bx + (3 - 2b) y = 3 + a$ possess a unique solution $x = 1, y = 1$ then :
If the system of equations, $a^2 x - ay = 1 - a$ & $bx + (3 - 2b) y = 3 + a$ possess a unique solution $x = 1, y = 1$ then :
- A
$a = 1 ; b = - 1$
- B
$a = - 1 , b = 1$
- C
$a = 0 , b = 0$
- D
none
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