If the sum of the first four terms of an $A.P.$ is $6$ and the sum of its first six terms is $4$,then the sum of its first twelve terms is

  • A
    -$20$
  • B
    -$24$
  • C
    -$26$
  • D
    -$22$

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In an $A.P.$,the first term is $2$ and the sum of the first five terms is one-fourth of the next five terms. Show that the $20^{th}$ term is $-112$.

Let $a_1, a_2, a_3, \ldots$ be in an arithmetic progression of positive terms. Let $A_{k}=a_1^2-a_2^2+a_3^2-a_4^2+\ldots+a_{2k-1}^2-a_{2k}^2$. If $A_3=-153$,$A_5=-435$ and $a_1^2+a_2^2+a_3^2=66$,then $a_{17}-A_7$ is equal to:

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