If the moment of inertia of a thin circular ring about an axis passing through its edge and perpendicular to its plane is $I$,then the moment of inertia of the ring about its diameter is

  • A
    $\frac{I}{4}$
  • B
    $4I$
  • C
    $\frac{I}{2}$
  • D
    $2I$

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