If the lines 2x + y - 3 = 0,5x + ky - 3 = 0,a | vedclass

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(B) Three lines are concurrent if they pass through a common point,meaning the point of intersection of any two lines lies on the third line.Given lin

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$-2$

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(B) Three lines are concurrent if they pass through a common point,meaning the point of intersection of any two lines lies on the third line.Given lines are:$2x + y - 3 = 0$ $(1)$$5x + ky - 3 = 0$ $(2)$$3x - y - 2 = 0$ $(3)$Solving $(1)$ and $(3)$ by adding them:$(2x + y - 3) + (3x - y - 2) = 0$$5x - 5 = 0 \implies x = 1$Substituting $x = 1$ into $(1)$:$2(1) + y - 3 = 0 \implies y = 1$The point of intersection is $(1, 1)$.Since the lines are concurrent,the point $(1, 1)$ must satisfy equation $(2)$:$5(1) + k(1) - 3 = 0$$5 + k - 3 = 0$$k + 2 = 0 \implies k = -2$

If the lines $2x + y - 3 = 0$,$5x + ky - 3 = 0$,and $3x - y - 2 = 0$ are concurrent,find the value of $k$.

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