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(B) Step $1$: Find the point of intersection of $4x - 3y = 1$ and $5x - 2y = 3$. Multiplying the first equation by $2$ and the second by $3$: $8x - 6y

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$3x - 2y = 1$

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(B) Step $1$: Find the point of intersection of $4x - 3y = 1$ and $5x - 2y = 3$. Multiplying the first equation by $2$ and the second by $3$: $8x - 6y = 2$ $15x - 6y = 9$ Subtracting the equations: $(15x - 8x) = 9 - 2 \implies 7x = 7 \implies x = 1$. Substituting $x = 1$ in $4(1) - 3y = 1 \implies 3y = 3 \implies y = 1$. The point of intersection is $(1, 1)$. Step $2$: The equation of a line parallel to $2y - 3x + 2 = 0$ is of the form $2y - 3x + k = 0$ or $3x - 2y = C$. Step $3$: Since the line passes through $(1, 1)$,substitute these coordinates into $3x - 2y = C$: $3(1) - 2(1) = C \implies C = 1$. Thus,the required equation is $3x - 2y = 1$.

The equation of the line passing through the point of intersection of the lines $4x - 3y - 1 = 0$ and $5x - 2y - 3 = 0$ and parallel to the line $2y - 3x + 2 = 0$ is:

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