If the lengths of two sides of a triangle are the roots of the equation $x^2-2 \sqrt{3} x+2=0$ and the angle between these sides is $\frac{\pi}{3}$,then the perimeter of the triangle is

  • A
    $2 \sqrt{6}+\sqrt{3}$
  • B
    $2 \sqrt{6}+2 \sqrt{3}$
  • C
    $\sqrt{6}+2 \sqrt{3}$
  • D
    $\sqrt{6}+\sqrt{3}$

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