(B) Let the length of the longer diagonal be $d_1 = x$.Then,the length of the shorter diagonal is $d_2 = 80\% \text{ of } x = 0.8x = \frac{4}{5}x$.The

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(B) Let the length of the longer diagonal be $d_1 = x$.Then,the length of the shorter diagonal is $d_2 = 80\% \text{ of } x = 0.8x = \frac{4}{5}x$.The area of a rhombus is given by the formula $A = \frac{1}{2} \times d_1 \times d_2$.Substituting the values,$A = \frac{1}{2} \times x \times \frac{4}{5}x = \frac{2}{5}x^2$.Thus,the area of the rhombus is $\frac{2}{5}$ times the square of the length of the longer diagonal.

Competitive Quantitative Aptitude Mensuration Measurement of Area

Medium

If the length of one diagonal of a rhombus is $80 \%$ of the length of the other diagonal,the area of the rhombus is how many times the square of the length of the longer diagonal?

A
$4/5$
B
$2/5$
C
$3/4$
D
$1/4$

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Measurement of Area

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If the length of one diagonal of a rhombus is $80 \%$ of the length of the other diagonal,the area of the rhombus is how many times the square of the length of the longer diagonal?

Similar Questions

In measuring the sides of a rectangle,one side is taken $5 \%$ in excess,and the other $4 \%$ in deficit. Find the error percent in the area calculated from these measurements. (in $\%$)

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$A$ steel sphere of radius $4 \, cm$ is drawn into a wire of diameter $4 \, mm$. Find the length of the wire in $mm$.

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