If the increase in the kinetic energy of a bo | vedclass

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(C) The relationship between momentum $P$ and kinetic energy $E$ is given by $P = \sqrt{2mE}$.Assuming mass $m$ is constant,we have $P \propto \sqrt{E

Vedclass · Accepted Answer

$10$

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(C) The relationship between momentum $P$ and kinetic energy $E$ is given by $P = \sqrt{2mE}$.Assuming mass $m$ is constant,we have $P \propto \sqrt{E}$.Let the initial kinetic energy be $E_1$ and the final kinetic energy be $E_2 = E_1 + 0.22E_1 = 1.22E_1$.The ratio of the final momentum $P_2$ to the initial momentum $P_1$ is $\frac{P_2}{P_1} = \sqrt{\frac{E_2}{E_1}} = \sqrt{1.22} \approx 1.1$.Thus,$P_2 = 1.1P_1 = (1 + 0.1)P_1 = P_1 + 0.1P_1$.This represents an increase of $0.1 	imes 100\% = 10\%$ in the momentum.

If the increase in the kinetic energy of a body is $22\%$,then the increase in the momentum will be ........... $\%$

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