A body is falling under gravity from rest. Wh | vedclass

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(C) According to the principle of conservation of mechanical energy,the loss in gravitational potential energy is equal to the gain in kinetic energy.

Vedclass · Accepted Answer

$\frac{2U}{v^2}$

Vedclass · Answer

(C) According to the principle of conservation of mechanical energy,the loss in gravitational potential energy is equal to the gain in kinetic energy.Given that the body starts from rest,the initial kinetic energy is $0$.Let $m$ be the mass of the body.The loss in potential energy is given as $U$.The gain in kinetic energy is $\frac{1}{2}mv^2 - 0 = \frac{1}{2}mv^2$.Equating the two: $U = \frac{1}{2}mv^2$.Solving for $m$: $m = \frac{2U}{v^2}$.

$A$ body is falling under gravity from rest. When it loses a gravitational potential energy by $U,$ its speed increases to $v.$ The mass of the body shall be

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