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(B) The given equation is $x(4 - kx) = 3 - 2x$.Expanding the equation: $4x - kx^2 = 3 - 2x$.Rearranging the terms to form the standard quadratic equat

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$3$

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(B) The given equation is $x(4 - kx) = 3 - 2x$.Expanding the equation: $4x - kx^2 = 3 - 2x$.Rearranging the terms to form the standard quadratic equation $ax^2 + bx + c = 0$: $kx^2 - 6x + 3 = 0$.For a quadratic equation to have two equal and real roots,the discriminant $D = b^2 - 4ac$ must be equal to $0$.Here,$a = k$,$b = -6$,and $c = 3$.Substituting these values into the discriminant formula: $(-6)^2 - 4(k)(3) = 0$.$36 - 12k = 0$.$12k = 36$.$k = 3$.

If the following quadratic equation has two equal and real roots,then find the value of $k$: $x(4 - kx) = 3 - 2x$.

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