If the first term of an $AP$ is $-5$ and the common difference is $2,$ then the sum of the first $6$ terms is

  • A
    $0$
  • B
    $5$
  • C
    $6$
  • D
    $15$

Explore More

Similar Questions

Find the number of terms of the finite $A.P.$ $-1, -\frac{5}{6}, -\frac{2}{3}, \ldots, \frac{10}{3}$.

For each of the following $A.P.s$,find the $n^{th}$ term: $\frac{4}{3}, 2, \frac{8}{3}, \frac{10}{3}, \ldots$

Solve the equation $-4 + (-1) + 2 + \ldots + x = 437$.

Difficult
View Solution

The sum of the first $15$ terms of the $A.P.$ $-10, -12, -14, -16, \ldots$ is:

Justify whether it is true to say that the following are the $n^{\text{th}}$ terms of an $AP.$
$(i)$ $2n-3$
$(ii)$ $3n^{2}+5$
$(iii)$ $1+n+n^{2}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo