If the equation of the locus of a point equidistant from the points $({a_1},{b_1})$ and $({a_2},{b_2})$ is $({a_1} - {a_2})x + ({b_1} - {b_2})y + c = 0$, then the value of $‘c’$ is
If the equation of the locus of a point equidistant from the points $({a_1},{b_1})$ and $({a_2},{b_2})$ is $({a_1} - {a_2})x + ({b_1} - {b_2})y + c = 0$, then the value of $‘c’$ is
- [IIT 2003]
- A
$\frac{1}{2}(a_2^2 + b_2^2 - a_1^2 - b_1^2)$
- B
$a_1^2 - a_2^2 + b_1^2 - b_2^2$
- C
$\frac{1}{2}(a_1^2 + a_2^2 + b_1^2 + b_2^2)$
- D
$\sqrt {a_1^2 + b_1^2 - a_2^2 - b_2^2} $
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