If the equation of the circle whose radius is $3$ units and which touches internally the circle $x^2+y^2-4x-6y-12=0$ at the point $(-1,-1)$ is $x^2+y^2+px+qy+r=0$,then $p+q-r=$

  • A
    $2$
  • B
    $\frac{5}{2}$
  • C
    $\frac{26}{5}$
  • D
    $3$

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