Weight of a body is maximum at

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The weight of a body is given by the formula $W = m 	imes g$,where $m$ is the mass of the body and $g$ is the acceleration due to gravity.Since t

Vedclass · Accepted Answer

Poles of earth

Vedclass · Answer

(B) The weight of a body is given by the formula $W = m 	imes g$,where $m$ is the mass of the body and $g$ is the acceleration due to gravity.Since the mass $m$ is constant,the weight $W$ is directly proportional to the acceleration due to gravity $g$.The value of $g$ on the surface of the Earth varies with latitude. It is given by $g = g_0 - \omega^2 R \cos^2 \phi$,where $\phi$ is the latitude.At the equator,$\phi = 0^\circ$,so $\cos^2 \phi$ is maximum,making $g$ minimum.At the poles,$\phi = 90^\circ$,so $\cos^2 \phi = 0$,making $g$ maximum.Therefore,the weight of a body is maximum at the poles of the Earth.Thus,the correct option is $B$.

Similar Questions

If the mass of the Sun were ten times smaller and the universal gravitational constant were ten times larger in magnitude,which of the following is not correct?

$A$ body weighs $300 \ N$ on the surface of the earth. How much will it weigh at a distance $\frac{R}{2}$ below the surface of the earth (in $N$)? ($R$ is the radius of the earth.)

If the radius of the Earth were to shrink by half,its mass remaining the same,what would be the weight of an object on its surface?

The period of a seconds pendulum on a planet,whose mass and radius are three times that of Earth,is

How does the force of gravity $F$ vary inside the Earth at a distance $r$ from the center,where $r < R_e$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module