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(B) The foci of an ellipse are given by $(\pm ae, 0)$.The distance between the foci is $2ae$.The length of the minor axis is $2b$.According to the giv

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$1/\sqrt{2}$

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(B) The foci of an ellipse are given by $(\pm ae, 0)$.The distance between the foci is $2ae$.The length of the minor axis is $2b$.According to the given condition,$2ae = 2b$,which implies $ae = b$.We know the relation for an ellipse: $b^2 = a^2(1 - e^2)$.Substituting $b = ae$ into the equation,we get $(ae)^2 = a^2(1 - e^2)$.$a^2e^2 = a^2(1 - e^2)$.Dividing both sides by $a^2$ (where $a 
eq 0$),we get $e^2 = 1 - e^2$.$2e^2 = 1$,which gives $e^2 = 1/2$.Therefore,$e = 1/\sqrt{2}$.

If the distance between the foci of an ellipse is equal to its minor axis,then its eccentricity is

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