If the dip circle is set at $45^{\circ}$ to the magnetic meridian,then the apparent dip is $30^{\circ}$. The true dip of the place is:

  • A
    $\tan^{-1}\left(\frac{1}{\sqrt{3}}\right)$
  • B
    $\tan^{-1}\left(\frac{1}{\sqrt{6}}\right)$
  • C
    $\tan^{-1}\left(\frac{2}{\sqrt{3}}\right)$
  • D
    $\tan^{-1}\left(\frac{\sqrt{3}}{2}\right)$

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Similar Questions

Which of the following statements proves that Earth has a magnetic field?

Assume the dipole model for Earth's magnetic field $B$,which is given by:
$B_v = \text{vertical component of magnetic field} = \frac{\mu_0}{4\pi} \frac{2m \cos \theta}{r^3}$
$B_H = \text{horizontal component of magnetic field} = \frac{\mu_0}{4\pi} \frac{m \sin \theta}{r^3}$
where $\theta = 90^{\circ} - \text{latitude}$ as measured from the magnetic equator.
$(a)$ Find the loci of points for which the dip angle is $\pm 45^{\circ}$.

The angle of dip at a certain place on earth is $60^{\circ}$ and the magnitude of earth's horizontal component of magnetic field is $0.26 \, G$. The magnetic field at the place on earth is.....$G$

At a certain place,the horizontal component of the Earth's magnetic field is $B_0$ and the angle of dip is $45^o$. The total intensity of the Earth's magnetic field at that place will be:

Let $m$ and $r$ be the dipole moment and radius of the Earth,respectively. Then,the Earth's magnetic field at the equator is

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