If the dip circle is set at $45^o$ to the magnetic meridian, then the apparent dip is $30^o$. The true dip. of the place is

  • A

    ${\tan ^{ - 1}}\,\left( {\frac{1}{{\sqrt 3 }}} \right)$

  • B

    ${\tan ^{ - 1}}\,\left( {\frac{1}{{\sqrt 6 }}} \right)$

  • C

    ${\tan ^{ - 1}}\,\left( {\frac{2}{{\sqrt 3 }}} \right)$

  • D

    ${\tan ^{ - 1}}\,\left( {\frac{{\sqrt 3 }}{2}} \right)$

Similar Questions

A compass needle whose magnetic moment is $60 \,amp × m^2$ pointing geographical north at a certain place, where the horizontal component of earth's magnetic field is $40\, \mu Wb/m^2$, experiences a torque $1.2 \times {10^{ - 3}}\,N \times m.$ What is the declination at this place......$^o$

Assertion : If a compass needle be kept at magnetic north pole of the earth the compass needle may stay in any direction.

Reason : Dip needle will stay vertical at the north pole of earth

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  • [JEE MAIN 2022]