The true value of angle of dip at a place is | vedclass

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Question

(b)$	an {\phi}' = \frac{{	an \phi }}{{\cos \beta }};$ where ${\phi }'$ = Apparent angle of dip,
$\phi $ = True angle of dip, $\beta $ = Ang

Vedclass · Accepted Answer

${	an ^{ - 1}}(2)$

Vedclass · Answer

(b)$	an {\phi}' = \frac{{	an \phi }}{{\cos \beta }};$ where ${\phi }'$ = Apparent angle of dip,
$\phi $ = True angle of dip, $\beta $ = Angle made by vertical plane with magnetic meridian.
$ \Rightarrow 	an {\phi }' = \frac{{	an {{60}^o}}}{{\cos {{30}^o}}} = 2 \Rightarrow {\phi }' = {	an ^{ - 1}}\left( 2 ight)$

The true value of angle of dip at a place is $60^o$, the apparent dip in a plane inclined at an angle of $30^o$ with magnetic meridian is

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