Two normal uniform magnetic field contain a magnetic needle making an angle $60°$ with $F$. Then the ratio of $\frac{F}{H}$ is
$1:2$
$2:1$
$\sqrt 3 :1$
$1:\sqrt 3 $
Earth's magnetic field always has a horizontal component except at or Horizontal component of earth's magnetic field remains zero at
The value of angle of dip is zero at the magnetic equator because on it
A line passing through places having zero value of magnetic dip is called
A current carrying coil is placed with its axis perpendicular to $ N-S $ direction. Let horizontal component of earth's magnetic field be $H_o$ and magnetic field inside the loop is $H$. If a magnet is suspended inside the loop, it makes angle $\theta $ with $H$. Then $\theta $$=$
If the dip circle is set at $45^o$ to the magnetic meridian, then the apparent dip is $30^o$. The true dip. of the place is