If the coordinates of one end of a diameter of the circle $x^2+y^2+4x-8y+5=0$ are $(2,1)$,then the coordinates of the other end are:

  • A
    $(-6,-7)$
  • B
    $(6,7)$
  • C
    $(-6,7)$
  • D
    $(7,-6)$

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