If the circle $S \equiv x^2+y^2+2gx+4y+1=0$ bisects the circumference of the circle $x^2+y^2-2x-3=0$,then the radius of circle $S=0$ is

  • A
    $5$
  • B
    $\sqrt{12}$
  • C
    $25$
  • D
    $12$

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