If the binding energy per nucleon of a nuclide is high,then:

The mass of a proton is $1.0073 \; u$ and that of a neutron is $1.0087 \; u$ ($u =$ atomic mass unit). The binding energy of ${ }_2^4 \text{He}$ is (Given: helium nucleus mass $\approx 4.0015 \; u$):

Two nuclei of mass number $3$ combine with another nucleus of mass number $4$ to yield a nucleus of mass number $10$. If the binding energy per nucleon for the mass numbers $3$,$4$,and $10$ are $5.6 \text{ MeV}$,$7.4 \text{ MeV}$,and $6.1 \text{ MeV}$,respectively,then in the process,$\Delta Mc^2 = . . . . . . \text{ MeV}$.

$A$ nucleus of mass $M + \Delta m$ is at rest and decays into two daughter nuclei of equal mass $\frac{M}{2}$ each. The speed of light is $c$. The speed of the daughter nuclei is:

Write the equation of mass-energy equivalence.

$M_n$ and $M_p$ represent the mass of a neutron and a proton, respectively. If an element having atomic mass $M$ has $N$ neutrons and $Z$ protons, then the correct relation is: