If the roots of x^2 - 7x + 6 = 0 are alpha an | vedclass

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(B) For a quadratic equation of the form $ax^2 + bx + c = 0$,the sum of the roots is $\alpha + \beta = -b/a$ and the product of the roots is $\alpha\b

Vedclass · Accepted Answer

$7/6$

Vedclass · Answer

(B) For a quadratic equation of the form $ax^2 + bx + c = 0$,the sum of the roots is $\alpha + \beta = -b/a$ and the product of the roots is $\alpha\beta = c/a$.Given the equation $x^2 - 7x + 6 = 0$,we have $a = 1$,$b = -7$,and $c = 6$.Therefore,the sum of the roots is $\alpha + \beta = -(-7)/1 = 7$.The product of the roots is $\alpha\beta = 6/1 = 6$.We need to find the value of $\frac{1}{\alpha} + \frac{1}{\beta}$.By taking the common denominator,we get $\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha\beta}$.Substituting the values,we get $\frac{7}{6}$.

If the roots of $x^2 - 7x + 6 = 0$ are $\alpha$ and $\beta$,then $\frac{1}{\alpha} + \frac{1}{\beta} = $

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If $\alpha$ and $\beta$ are the roots of the equation $x^2 + ax + b = 0$,then the value of $\alpha^3 + \beta^3$ is equal to:

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