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(D) Step $1$: Solve for $x$.$x = \sqrt{(36)^{1/2} 	imes (1296)^{1/4}} = \sqrt{6 	imes 6} = \sqrt{36} = 6$.Step $2$: Solve the system of linear equat

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if $x = y$ or relationship between $x$ and $y$ cannot be established.

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(D) Step $1$: Solve for $x$.$x = \sqrt{(36)^{1/2} 	imes (1296)^{1/4}} = \sqrt{6 	imes 6} = \sqrt{36} = 6$.Step $2$: Solve the system of linear equations for $y$.Given equations:$(ii) \quad 2y + 3z = 33$$(iii) \quad 6y + 5z = 71$Multiply equation $(ii)$ by $3$:$6y + 9z = 99$Subtract equation $(iii)$ from this result:$(6y + 9z) - (6y + 5z) = 99 - 71$$4z = 28 \Rightarrow z = 7$.Substitute $z = 7$ into equation $(ii)$:$2y + 3(7) = 33$$2y + 21 = 33$$2y = 12 \Rightarrow y = 6$.Step $3$: Compare $x$ and $y$.Since $x = 6$ and $y = 6$,we have $x = y$.

Solve the given equations and choose the correct option.
$I.$ $x = \sqrt{(36)^{1/2} \times (1296)^{1/4}}$
$II.$ $2y + 3z = 33$
$III.$ $6y + 5z = 71$

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Solve the given equations and choose the correct option.$I.$ $x = \sqrt{(36)^{1/2} \times (1296)^{1/4}}$$II.$ $2y + 3z = 33$$III.$ $6y + 5z = 71$